Find the value of x and y.

3x + 7y = 41

12x + 5y = 26- 7/3, 6
- -1/3, 6
- -11/4, 14
- 11/4, 14
- -13/5, 8

Option 2 : -1/3, 6

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⇒ 3x + 7y = 41 ……..q1

⇒ 12x + 5y = 26 ………eq2

Multiplying equation 1 by 4 we get

⇒ 12x + 28y = 164 …….eq3

Subtracting eq 2 from eq 3 we get

⇒ 23y = 138

⇒ y = 138/23 = 6

Putting the value of y in eq 1 we get

⇒ 3x + 42 = 41

⇒ 3x = 41 – 42 = -1

⇒ x = - 1/3

∴ Value of x is – 1/3 and y is 6
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